Integrand size = 11, antiderivative size = 52 \[ \int \frac {x^3}{(a+b x)^7} \, dx=\frac {x^4}{6 a (a+b x)^6}+\frac {x^4}{15 a^2 (a+b x)^5}+\frac {x^4}{60 a^3 (a+b x)^4} \]
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Time = 0.02 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.23, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {45} \[ \int \frac {x^3}{(a+b x)^7} \, dx=\frac {a^3}{6 b^4 (a+b x)^6}-\frac {3 a^2}{5 b^4 (a+b x)^5}+\frac {3 a}{4 b^4 (a+b x)^4}-\frac {1}{3 b^4 (a+b x)^3} \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {a^3}{b^3 (a+b x)^7}+\frac {3 a^2}{b^3 (a+b x)^6}-\frac {3 a}{b^3 (a+b x)^5}+\frac {1}{b^3 (a+b x)^4}\right ) \, dx \\ & = \frac {a^3}{6 b^4 (a+b x)^6}-\frac {3 a^2}{5 b^4 (a+b x)^5}+\frac {3 a}{4 b^4 (a+b x)^4}-\frac {1}{3 b^4 (a+b x)^3} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.81 \[ \int \frac {x^3}{(a+b x)^7} \, dx=-\frac {a^3+6 a^2 b x+15 a b^2 x^2+20 b^3 x^3}{60 b^4 (a+b x)^6} \]
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Time = 0.03 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.79
method | result | size |
gosper | \(-\frac {20 b^{3} x^{3}+15 a \,b^{2} x^{2}+6 a^{2} b x +a^{3}}{60 \left (b x +a \right )^{6} b^{4}}\) | \(41\) |
norman | \(\frac {-\frac {x^{3}}{3 b}-\frac {a \,x^{2}}{4 b^{2}}-\frac {a^{2} x}{10 b^{3}}-\frac {a^{3}}{60 b^{4}}}{\left (b x +a \right )^{6}}\) | \(44\) |
risch | \(\frac {-\frac {x^{3}}{3 b}-\frac {a \,x^{2}}{4 b^{2}}-\frac {a^{2} x}{10 b^{3}}-\frac {a^{3}}{60 b^{4}}}{\left (b x +a \right )^{6}}\) | \(44\) |
parallelrisch | \(\frac {-20 b^{5} x^{3}-15 a \,b^{4} x^{2}-6 a^{2} b^{3} x -a^{3} b^{2}}{60 b^{6} \left (b x +a \right )^{6}}\) | \(48\) |
default | \(-\frac {3 a^{2}}{5 b^{4} \left (b x +a \right )^{5}}+\frac {a^{3}}{6 b^{4} \left (b x +a \right )^{6}}+\frac {3 a}{4 b^{4} \left (b x +a \right )^{4}}-\frac {1}{3 b^{4} \left (b x +a \right )^{3}}\) | \(57\) |
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Leaf count of result is larger than twice the leaf count of optimal. 98 vs. \(2 (46) = 92\).
Time = 0.22 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.88 \[ \int \frac {x^3}{(a+b x)^7} \, dx=-\frac {20 \, b^{3} x^{3} + 15 \, a b^{2} x^{2} + 6 \, a^{2} b x + a^{3}}{60 \, {\left (b^{10} x^{6} + 6 \, a b^{9} x^{5} + 15 \, a^{2} b^{8} x^{4} + 20 \, a^{3} b^{7} x^{3} + 15 \, a^{4} b^{6} x^{2} + 6 \, a^{5} b^{5} x + a^{6} b^{4}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 104 vs. \(2 (42) = 84\).
Time = 0.22 (sec) , antiderivative size = 104, normalized size of antiderivative = 2.00 \[ \int \frac {x^3}{(a+b x)^7} \, dx=\frac {- a^{3} - 6 a^{2} b x - 15 a b^{2} x^{2} - 20 b^{3} x^{3}}{60 a^{6} b^{4} + 360 a^{5} b^{5} x + 900 a^{4} b^{6} x^{2} + 1200 a^{3} b^{7} x^{3} + 900 a^{2} b^{8} x^{4} + 360 a b^{9} x^{5} + 60 b^{10} x^{6}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 98 vs. \(2 (46) = 92\).
Time = 0.20 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.88 \[ \int \frac {x^3}{(a+b x)^7} \, dx=-\frac {20 \, b^{3} x^{3} + 15 \, a b^{2} x^{2} + 6 \, a^{2} b x + a^{3}}{60 \, {\left (b^{10} x^{6} + 6 \, a b^{9} x^{5} + 15 \, a^{2} b^{8} x^{4} + 20 \, a^{3} b^{7} x^{3} + 15 \, a^{4} b^{6} x^{2} + 6 \, a^{5} b^{5} x + a^{6} b^{4}\right )}} \]
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none
Time = 0.30 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.77 \[ \int \frac {x^3}{(a+b x)^7} \, dx=-\frac {20 \, b^{3} x^{3} + 15 \, a b^{2} x^{2} + 6 \, a^{2} b x + a^{3}}{60 \, {\left (b x + a\right )}^{6} b^{4}} \]
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Time = 0.08 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.92 \[ \int \frac {x^3}{(a+b x)^7} \, dx=\frac {\frac {3\,a}{4\,{\left (a+b\,x\right )}^4}-\frac {1}{3\,{\left (a+b\,x\right )}^3}-\frac {3\,a^2}{5\,{\left (a+b\,x\right )}^5}+\frac {a^3}{6\,{\left (a+b\,x\right )}^6}}{b^4} \]
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